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Char and bool

C# course · Beginner · Lesson 15/116

Learn to store single characters with char and logical values with bool.

Type conversion

Sometimes you need to convert one type to another. Implicit conversion happens automatically from a smaller type to a larger one: double d = 5; turns the int 5 into a double.

Explicit conversion (cast) goes from large to small; because data may be lost, you must ask for it: int n = (int)3.9; gives 3.

A cast writes the type name in parentheses. Implicit conversion is safe; explicit casting puts the responsibility on you.

Convert and Parse

When you need to turn a string into a number, two options exist. int.Parse("42") converts the text directly to an int; it throws on invalid input.

Convert.ToInt32("7") does the same; the Convert class gathers many type conversions under one roof.

Both throw an exception on null or non-numeric text. You will learn TryParse for safe parsing in later lessons.

Exercise Parse a string into an int

Assign "42" to a string text variable. Convert it into an int number using int.Parse(text). Then print number + 10 with Console.WriteLine.

Show example solution
string text = "42"; int number = int.Parse(text); Console.WriteLine(number + 10);
Example solution:
using System;
class Program {
    static void Main() {
        string text = "42";
        int number = int.Parse(text);
        Console.WriteLine(number + 10);
    }
}

Test yourself

  1. Which one is an implicit conversion?

    • double d = 5;
    • int n = 3.14;
    • int n = (int)3.14;
    • string s = "5";
    Show answer

    double d = 5; — Correct! Implicit int-to-double conversion is safe; no cast needed.

  2. Explicitly cast a double to int

    int n = ____ 3.9;
    Show answer
    int n = (int) 3.9;
  3. Match each conversion to its purpose

    (int)3.9
    cast to truncate
    int.Parse("42")
    string to int
    Convert.ToInt32("7")
    Convert class
    double d = 5
    implicit widen

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