GET

Learn GET requests with http.get.

GET requests

get(url) makes a GET request. url is a Uri. The returned Response's statusCode and body fields are read.

Example: var r = await get(Uri.parse('https://api.example.com/users')); print(r.statusCode); print(r.body);. 200 means success; body is JSON text.

GET requests carry no body; parameters go in the URL as a query string: Uri.parse('...?page=2').

Query strings

To add parameters to a URL, use the queryParameters field of Uri: Uri(scheme: 'https', host: 'api.example.com', path: '/users', queryParameters: {'page': '2'}).

This produces a query string like ?page=2. This structural method is preferred over manual string concatenation.

Multiple parameters are joined with & automatically; URL encoding is done automatically.

Exercise Build a Uri with query

Inside main add var u = Uri(scheme: 'https', host: 'api.example.com', path: '/users', queryParameters: {'page': '2'});. Add print(u.host); and print(u.query);.

Show example solution

void main() {
  var u = Uri(
    scheme: 'https',
    host: 'api.example.com',
    path: '/users',
    queryParameters: {'page': '2'},
  );
  print(u.host);
  print(u.query);
}

Test yourself

GET call

var r = await ____(Uri.parse(url));

Show answer

var r = await get(Uri.parse(url));

Does a GET request have a body?
- Only form
- Yes, always
- Only JSON
- No, parameters go in the URL
Show answer

No, parameters go in the URL — GET carries no body; parameters go in the URL as a query string.
Match the GET parts

get(Uri)

Request function
statusCode

200
body

Response body
queryParameters

URL parameters

Next lesson: POST

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