reflect.Type
- Go course
- Advanced
- Lesson 2/68
- 4 min
Learn to get type info with Type.
reflect.Type
reflect.TypeOf(v) returns a reflect.Type. Name() gives the type's name and Kind() its underlying kind.
type Kullanici struct{ Ad string }
t := reflect.TypeOf(Kullanici{})
fmt.Println(t.Name(), t.Kind()) // Kullanici structThe name is the one you chose; the kind comes from a fixed list such as struct, int, slice, map.
Branching on Kind
A generic function can behave differently depending on the kind of the incoming value:
switch reflect.TypeOf(v).Kind() {
case reflect.Int:
fmt.Println("tamsayı")
case reflect.Slice:
fmt.Println("dilim")
}Kind constants are defined in the package with names like reflect.Int, reflect.String, reflect.Struct.
Practice Name and kind
Define type Urun struct{ Fiyat int }. In main, get t := reflect.TypeOf(Urun{}) and print t.Name() and t.Kind() with one fmt.Println.
Starter code
package main
import (
"fmt"
"reflect"
)
func main() {
// buraya yaz
}Sample solution
package main
import (
"fmt"
"reflect"
)
type Urun struct{ Fiyat int }
func main() {
t := reflect.TypeOf(Urun{})
fmt.Println(t.Name(), t.Kind())
}Expected output
Urun struct
Questions and answers
Review the lesson questions together with their answers. To test yourself, solve the lesson interactively.
1 For <code>type Yas int</code>, what does <code>reflect.TypeOf(Yas(5)).Kind()</code> return?
- int Correct answer
- Yas
- struct
- main.Yas
Explanation: Kind gives the underlying kind; Yas is a defined type but its base is int. Name() would return "Yas".
2 Get the kind
t := reflect.TypeOf([]int{1, 2})
fmt.Println(t.____()) // slicet := reflect.TypeOf([]int{1, 2})
fmt.Println(t.Kind()) // sliceExplanation: Kind() returns the underlying kind; for []int it is slice.
3 Value and its kind
| Term | Meaning |
|---|---|
42 |
int |
"Go" |
string |
[]int{1} |
slice |
map[string]int{} |
map |